document.write( "Question 125802: Two cars start from towns 400 mi apart and travel toward each other. They meet after 4 hrs. Find the speed of each car if one travels 20mph faster than the other. \n" ); document.write( "
Algebra.Com's Answer #92183 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two cars start from towns 400 mi apart and travel toward each other. They meet after 4 hrs. Find the speed of each car if one travels 20mph faster than the other. \n" ); document.write( ": \n" ); document.write( "Let s = speed of the slower car \n" ); document.write( "then \n" ); document.write( "(s+20) = speed of the faster \n" ); document.write( ": \n" ); document.write( "When they meet, we know they will have traveled a total of 400 mi. \n" ); document.write( ": \n" ); document.write( "Make a distance equation: Distance = time * speed \n" ); document.write( ": \n" ); document.write( "Slow car dist + fast car dist = 400 miles \n" ); document.write( "4s + 4(s+20) = 400 \n" ); document.write( ": \n" ); document.write( "4s + 4s + 80 = 400 \n" ); document.write( ": \n" ); document.write( "8x = 400 - 80 \n" ); document.write( "s = \n" ); document.write( "s = 40 mph is the slow car \n" ); document.write( "and \n" ); document.write( "60 mph is the fast car \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can check our solution by finding the total distance: \n" ); document.write( "4(40) + 4(60) = 400 \n" ); document.write( " |