document.write( "Question 125798: Given f(x)= 5x^2-3x+1, find f(-2) \n" ); document.write( "
Algebra.Com's Answer #92170 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
To do this problem you start with the given function:
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\n" ); document.write( "\"f%28x%29=+5x%5E2-3x%2B1\"
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\n" ); document.write( "When you see f(-2) all that means is for you to go to the given function, replace every x with
\n" ); document.write( "-2 and simplify the answer.
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\n" ); document.write( "So you start with:
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\n" ); document.write( "\"f%28x%29=+5x%5E2-3x%2B1\"
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\n" ); document.write( "wherever you see an x replace it with -2 and you get:
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\n" ); document.write( "\"f%28-2%29+=+5%28-2%29%5E2+-+3%28-2%29+%2B+1\"
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\n" ); document.write( "For the first term on the right side you square the -2 to get +4 and you multiply that
\n" ); document.write( "by 5 to get +20. For the second term on the right side you multiply the -3 by the -2 and
\n" ); document.write( "you get +6. Substituting these two results into the equation gives:
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\n" ); document.write( "\"f%28-2%29+=+20+%2B+6+%2B+1\"
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\n" ); document.write( "This means that the answer is:
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\n" ); document.write( "\"f%28-2%29+=+27\"
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\n" ); document.write( "And that's the answer to this problem.
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\n" ); document.write( "Hope this helps you to understand in general how, when you are given f(x), you can find
\n" ); document.write( "f(A) ... just substitute A wherever you see an x in f(x).
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