document.write( "Question 125635This question is from textbook algebra 1
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document.write( ": im sorry....it's me again, i think you read my problem wrong, it was\r
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document.write( "5b+8 divided by 3<3b\r
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document.write( "can you show me how to do that, thank you \n" );
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Algebra.Com's Answer #92150 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! IF YOU MEAN: \n" ); document.write( "(5B+8)/3<3B THEN WE CROSS MULTIPLY. \n" ); document.write( "5B+8<9B \n" ); document.write( "5B-9B<-8 \n" ); document.write( "-4B<-8 \n" ); document.write( "B>-8/-4 [HERE WE HAVE TO CHANCE THE < SIGN TO A > SIGN BECAUSE WE DIVIDED BY A NEGATIVE NUMBER. \n" ); document.write( "B>2 \n" ); document.write( "PROOF \n" ); document.write( "LET B=2.1 \n" ); document.write( "(5*2.1+8)/3<3*2.1 \n" ); document.write( "(10.5+8)/3<6.3 \n" ); document.write( "18.5/3<6.3 \n" ); document.write( "6.167<6.3 \n" ); document.write( " |