document.write( "Question 125635This question is from textbook algebra 1
\n" ); document.write( ": im sorry....it's me again, i think you read my problem wrong, it was\r
\n" ); document.write( "\n" ); document.write( "#26-
\n" ); document.write( "5b+8 divided by 3<3b\r
\n" ); document.write( "\n" ); document.write( "can you show me how to do that, thank you
\n" ); document.write( "

Algebra.Com's Answer #92150 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
IF YOU MEAN:
\n" ); document.write( "(5B+8)/3<3B THEN WE CROSS MULTIPLY.
\n" ); document.write( "5B+8<9B
\n" ); document.write( "5B-9B<-8
\n" ); document.write( "-4B<-8
\n" ); document.write( "B>-8/-4 [HERE WE HAVE TO CHANCE THE < SIGN TO A > SIGN BECAUSE WE DIVIDED BY A NEGATIVE NUMBER.
\n" ); document.write( "B>2
\n" ); document.write( "PROOF
\n" ); document.write( "LET B=2.1
\n" ); document.write( "(5*2.1+8)/3<3*2.1
\n" ); document.write( "(10.5+8)/3<6.3
\n" ); document.write( "18.5/3<6.3
\n" ); document.write( "6.167<6.3
\n" ); document.write( "
\n" );