document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125456>Question 125456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me with this problem?<BR>\n" );
document.write( "If the population of a town is currently 350,000 and increasing at a rate of 3.25% each year, approximately when will the population reach 1,000,000 assuming it maintains this steady rate of growth?<BR>\n" );
document.write( "My answer options are:<BR>\n" );
document.write( "a.33.8 yrs<BR>\n" );
document.write( "b.3.73 yrs<BR>\n" );
document.write( "c.32.8 yrs<BR>\n" );
document.write( "d.17.5 yrs<BR>\n" );
document.write( "Please get back to me as soon as possible, I am homeschooled but on a deadline to get this finished, thanks!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92127 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the population of a town is currently 350,000 and increasing at a rate of 3.25% each year, approximately when will the population reach 1,000,000 assuming it maintains this steady rate of growth?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let t = no. of years for this to occur<BR>\n" );
document.write( ":<BR>\n" );
document.write( "We know the population in  1 yr, we can multiply 350,000 by 1.0325, <BR>\n" );
document.write( "therefore, the equation will be:<BR>\n" );
document.write( ":<BR>\n" );
document.write( "350000*(1.0325)^t = 1000000 <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Divide both sides by 350000<BR>\n" );
document.write( "1.0325^t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1000000%2F350000 ALIGN=MIDDLE  ALT=\"1000000%2F350000\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "1.0325^t = 2.857<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Use the nat log of both sides:<BR>\n" );
document.write( "ln(1.0325^t) = ln(2.857)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The log equivalent of exponents:<BR>\n" );
document.write( "t * ln(1.0325) = ln(2.857)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the nat log of both sides:<BR>\n" );
document.write( ".03198t = 1.04977<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.04977%2F.03198 ALIGN=MIDDLE  ALT=\"1.04977%2F.03198\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = 32.8258 ~ 32.8<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check solution on a good calc; enter 350000 * l.0325^32.8 = 999222 ~ 1000000<BR>\n" );
document.write( ":<BR>\n" );
document.write( "You can try the other solutions and see which one is closest to 1,000,000\r<BR>\n" );
document.write( "\n" );
document.write( "~ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );