document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125728>Question 125728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi....so i really need help i just cant understan direct joint and inverse variations....so ok here is the problem.  \r<BR>\n" );
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document.write( "Q: if y varies directly as x and y=9 when x=6, find y when x=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92114 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if y varies directly as x and y=9 when x=6, find y when x=8<BR>\n" );
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document.write( "If y varies directly as x, y = kx<BR>\n" );
document.write( "You 1st need to solve for \"k\":<BR>\n" );
document.write( "9 = k*6<BR>\n" );
document.write( "k= 3/2<BR>\n" );
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document.write( "So the proper equation for your problem is <BR>\n" );
document.write( "y = (3/2)x<BR>\n" );
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document.write( "Then, if x = 8 you can solve for \"y\":<BR>\n" );
document.write( "y = (3/2)*8 = 12<BR>\n" );
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document.write( "Comment:<BR>\n" );
document.write( "If you have indirect variation y = k/x<BR>\n" );
document.write( "Joint is the same as direct<BR>\n" );
document.write( "inverse is the same as indirect<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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