document.write( "Question 125675: Solve for the unknown variable:
\n" ); document.write( "a)sqrt9^x=27
\n" ); document.write( "b)8^(1/2x)=(2^7)*(4^9)
\n" ); document.write( "c)sqrt125^x=5/25^x Can someone PLEASE help me ???
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Algebra.Com's Answer #92102 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
a) \"sqrt%289%5Ex%29=27\"\r
\n" ); document.write( "\n" ); document.write( "Square both sides:\r
\n" ); document.write( "\n" ); document.write( "\"9%5Ex=27%5E2\" (Don't bother calculating \"27%5E2\", it won't be necessary)\r
\n" ); document.write( "\n" ); document.write( "But \"9=3%5E2\" and \"27=3%5E3\", so\r
\n" ); document.write( "\n" ); document.write( "\"%283%5E2%29%5Ex=%283%5E3%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Use the rule: \"%28x%5Em%29%5En=x%5Emn\"\r
\n" ); document.write( "\n" ); document.write( "\"3%5E%282x%29=3%5E6\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"2x=6\"
\n" ); document.write( "\"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"9%5E3=729\"
\n" ); document.write( "\"sqrt%28729%29=27\", answer checks.\r
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\n" ); document.write( "\n" ); document.write( "b) Do you mean: \"8%5E%281%2F2x%29=%282%5E7%29%2A%284%5E9%29\" or do you really mean: \"8%5E%28%281%2F2%29x%29=%282%5E7%29%2A%284%5E9%29\"\r
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\n" ); document.write( "\n" ); document.write( "Either way: Notice that \"8=2%5E3\" and \"4=2%5E2\", so:\r
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\n" ); document.write( "\n" ); document.write( "Either:
\n" ); document.write( "\"2%5E%283%2F2x%29=%282%5E7%29%2A%282%5E18%29=2%5E25\"
\n" ); document.write( "or
\n" ); document.write( "\"2%5E%28%283%2F2%29x%29=%282%5E7%29%2A%282%5E18%29=2%5E25\"\r
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\n" ); document.write( "\n" ); document.write( "So either \"3%2F2x=25\" or \"%283x%2F2%29=25\"\r
\n" ); document.write( "\n" ); document.write( "And \"x=3%2F50\" or \"x=50%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "You should be able to use the same techniques to solve the last one. For part c get everything represented by powers of 5. \"25=5%5E2\" and \"125=5%5E3\"
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