document.write( "Question 125695: Please help me solve: 6/i - 8/8-i. Combine and write the answer in standard form. \n" ); document.write( "
Algebra.Com's Answer #92083 by solver91311(24713)\"\" \"About 
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\"6%2Fi+-+8%2F%288-i%29\".\r
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\n" ); document.write( "\n" ); document.write( "The first thing to do is rationalize the denominators, i.e. get the i out of each denominator and then you will be able to find a LCD to allow you to add the fractions.\r
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\n" ); document.write( "\n" ); document.write( "The first fraction is easy, you just multiply by \"i%2Fi\", giving you \"-6i%2F1\" (remember \"i%5E2=-1\")\r
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\n" ); document.write( "\n" ); document.write( "The other fraction requires you to remember the factorization of the difference of two squares. \"a%5E2-b%5E2=%28a%2Bb%29%28a-b%29\". Using this, we could multiply the denominator of the second fraction, \"8-i\" by its conjugate \"8%2Bi\" to obtain \"8%5E2-i%5E2=64%2B1=65\", but to do that we also have to multiply the numerator by the same thing. The result is that the second fraction looks like\"-%288%288%2Bi%29%29%2F65\"\r
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\n" ); document.write( "\n" ); document.write( "Putting it all together we get \"-%286i%2F1%29-%288%288%2Bi%29%29%2F65\"\r
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\n" ); document.write( "\n" ); document.write( "65 is clearly the LCD, so\r
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\n" ); document.write( "\n" ); document.write( "\"%28-390i-64-8i%29%2F65=red%28%28-64%2F65%29-%28398i%2F65%29%29\"
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