document.write( "Question 125696: looking for the standard deviation for these numbers.\r
\n" ); document.write( "\n" ); document.write( "38 45 47 47 48 50 50 52 58 62
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\n" ); document.write( "62 63 64 68 70 72 72 72 72 74
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\n" ); document.write( "78 79 80 80 82 84 88 90 94 99\r
\n" ); document.write( "\n" ); document.write( "First I add all numbers to find the mean. 2040/30=68
\n" ); document.write( "here is where I get lost. \r
\n" ); document.write( "\n" ); document.write( "I subtract the lowest number from the mean. 38-68=-30
\n" ); document.write( "and subtract the largest number from the mean. 99-68=31
\n" ); document.write( "I square them and add them together and that is where I get stuck.\r
\n" ); document.write( "\n" ); document.write( "(-30*-30)=900 (31*31)=961. 900+961=1861 Now am I supposed to divide by 2 or 30\r
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\n" ); document.write( "\n" ); document.write( "I am a little confused.\r
\n" ); document.write( "\n" ); document.write( "Darrin
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Algebra.Com's Answer #92079 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
You need to subtract the mean from EACH of the 30 data points.
\n" ); document.write( "Then square EACH of the differences.
\n" ); document.write( "Then add up all of the squared differences.
\n" ); document.write( "Divide this sum of squares by the number of data points minus 1 (29) (this is because you are doing a sample of a population).
\n" ); document.write( "Take the square root of the quotient.\r
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\n" ); document.write( "\n" ); document.write( "\"sigma=sqrt%28%281%2F%28N-1%29%29%2Asum%28%28x%5Bi%5D-x%5Bbar%5D%29%5E2%2Ci=1%2CN%29%29\" \"x%5Bbar%5D\" is the mean of your sample.\r
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\n" ); document.write( "\n" ); document.write( "Drop me a line and I'll send you a spreadsheet that shows all of the calculations.
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