document.write( "Question 125633: The length of a rectangle is 3 m more than twice its width. If the perimeter of the rectangle is 42 m, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #92073 by benni1013(206)\"\" \"About 
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We know the following: P=42 m, P=2l+2w
\n" ); document.write( "Connections: l=2w+3
\n" ); document.write( "Want to know: the dimensions of the rectangle\r
\n" ); document.write( "\n" ); document.write( "Calculations: First substitute the l=2w+3 into the perimeter formula.
\n" ); document.write( "P=2(2w+3)+2w. Multiply across. 4w+6+2w. Combine like terms. 6w+6.
\n" ); document.write( "Enter this expression into the perimeter equation. 42=6w+6. Subtract 6.
\n" ); document.write( "36=6w. Divide. w=6. Now put this answer into the length equation given.
\n" ); document.write( "l=2(6)+3. Multiply. l=12+3. Add. l=15. You now have your dimensions.
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