document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125679>Question 125679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x:<BR>\n" );
document.write( "A)(3^2x)-(10(3)^x) +9=0<BR>\n" );
document.write( "B)(3^x)*(3^(x+3))/(27^x)*(9^2x)=729 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92058 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (A) (3^2x)-(10(3)^x) +9=0<BR>\n" );
document.write( "Let 3^x = k<BR>\n" );
document.write( "then k^2 - 10k + 9 = 0<BR>\n" );
document.write( "==> k^2 - k - 9k + 9 = 0<BR>\n" );
document.write( "==> k(k - 1) - 9(k - 1) = 0<BR>\n" );
document.write( "==> (k-1) (k-9) = 0<BR>\n" );
document.write( "==> k-i = 0 or k - 9 = 0<BR>\n" );
document.write( "==> k = 1  or k = 9<BR>\n" );
document.write( "==> 3^x = 1 or 3^x = 9<BR>\n" );
document.write( "==> x = 0  or x = 2<BR>\n" );
document.write( "B)(3^x)*(3^(x+3))/(27^x)*(9^2x)=729<BR>\n" );
document.write( "3^(x+x+3) / 3^(3x+4x) = 3 ^ 6<BR>\n" );
document.write( "==> 2x+3-7x = 6<BR>\n" );
document.write( "==> - 5x + 3 = 6<BR>\n" );
document.write( "==> - 5x = 3<BR>\n" );
document.write( "==> x = -3/5\r<BR>\n" );
document.write( "\n" );
document.write( "good luck!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );