document.write( "Question 125690: One number is 12 more than another.The sum of the smaller number and twice the larger number is 39. Find the larger number. \n" ); document.write( "

Algebra.Com's Answer #92051 by MathLover1(20855) $\"\"$ $\"About$

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One number (let it be $\"x\"$ ) is $\"12\"$ more than another(let it be $\"y\"$ ).\r
\n" ); document.write( "\n" ); document.write( "assume $\"x%3Cy\"$ , then $\"y+=+x+%2B+12\"$ \r
\n" ); document.write( "\n" ); document.write( "The sum of the smaller number and twice the larger number is $\"39\"$ :\r
\n" ); document.write( "\n" ); document.write( " $\"x+%2B+2y+=+39\"$ \r
\n" ); document.write( "\n" ); document.write( "since $\"y+=x+%2B+12\"$ , we will have;\r
\n" ); document.write( "\n" ); document.write( " $\"x+%2B+2%28x+%2B+12%29=+39\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+%2B+2x+%2B+24+=+39\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+3x++=+39+-24\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+3x++=+15\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+x++=+5\"$ \r
\n" ); document.write( "\n" ); document.write( " the larger number will be:\r
\n" ); document.write( "\n" ); document.write( " $\"y+=x+%2B+12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y+=+5+%2B+12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y+=++17\"$ \r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( " $\"x+%2B+2y+=+39\"$ ...plug in $\"x\"$ and $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"5+%2B+2%2817%29=+39\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"5+%2B+34+=+39\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"39+=+39\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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