document.write( "Question 125684This question is from textbook Intermediate Algebra Review
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document.write( "Bill and Chris left the student union at the same time on bicycles. Bill traveled east, and Chris traveled west. After 1/2 hour, they were 14 miles apart. If Bill was going 2 miles per hour faster than Chris, how fast was each of the bicycles going? \n" );
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Algebra.Com's Answer #92046 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Bill and Chris left the student union at the same time on bicycles. Bill traveled east, and Chris traveled west. After 1/2 hour, they were 14 miles apart. If Bill was going 2 miles per hour faster than Chris, how fast was each of the bicycles going? \n" ); document.write( "-------------- \n" ); document.write( "Bill DATA: \n" ); document.write( "Rate = x+2 mph ; Time = 1/2 hr ; distance = rt = (x+2)/2 miles \n" ); document.write( "------------------ \n" ); document.write( "Chris DATA: \n" ); document.write( "Rate = x mph ; Time = 1/2 hr ; distance = rt = x/2 miles \n" ); document.write( "------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "distance + distance = 14 miles \n" ); document.write( "(x+2)/2 + x/2 = 14 \n" ); document.write( "(x+2) + x = 28 \n" ); document.write( "2x = 26 \n" ); document.write( "x = 13 mph ( Chris rate) \n" ); document.write( "x+2= 15 mph ( Bill Rate) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |