document.write( "Question 125671: Find the minimum distance between f(x)=x^2 and y=2x-5 \n" ); document.write( "
Algebra.Com's Answer #92044 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
let's first graph given parabola \"y=x%5E2\" and a line \"y=2x-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28+600%2C+400%2C+-10%2C+10%2C+-20%2C+20%2C+x%5E2%2C+2x-5%29+\"\r
\n" ); document.write( "\n" ); document.write( "as you can see, there are no points of intersection\r
\n" ); document.write( "\n" ); document.write( "on a graph above we have given parabola \"y=x%5E2\" and line \"2x-5\"\r
\n" ); document.write( "\n" ); document.write( "now, I will add a line \"2x-1\" parallel to the given line \"2x-5\"(these lines have same slopes) which will be a tangent (there will be one point of intersection) on parabola \"x%5E2\"; the distance between these two parallel lines will be equal to the distance between the given line and parabola\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28+600%2C+400%2C+-10%2C+10%2C+-20%2C+20%2C+x%5E2%2C+2x-5%2C+2x-1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "now, we can choose two points (one on each of parallel lines) and find a distance between them; it will be also equal to the distance between parabola and the given line\r
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Solved by pluggable solver: Distance between two points in two dimensions
The distance (denoted by d) between two points in two dimensions is given by the following formula:
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\n" ); document.write( " \"d=sqrt%28%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2%29\"
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\n" ); document.write( " Thus in our case, the required distance is
\n" ); document.write( " \"d=sqrt%28%280-0%29%5E2+%2B+%28-1--5%29%5E2%29=+4+\"
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\n" ); document.write( " For more on this concept, refer to Distance formula.
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\n" ); document.write( "\n" ); document.write( "answer is: the distance is \"4\"
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