document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125502>Question 125502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please show me how to work this problem <BR>\n" );
document.write( "find all the zeros of the function and write the polynomial as a product of linear factors<BR>\n" );
document.write( "h(x)=x^3-11x^2-15x+325 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #92019 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=92019\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the 15 and 325 coefficients suggest that + or - 5 could be a root __ -5 makes the function zero<BR>\n" );
document.write( "__ so (x+5) is a factor\r<BR>\n" );
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document.write( "factoring out (x+5) leaves x^2-16x+65 __ use the quadratic formula to find the two other zeroes </SPAN>\n" );
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