document.write( "Question 125444: How many liters of pure acid must be mixed with 20 liters of a 15% acid solution to get 20% mixture? \n" ); document.write( "

Algebra.Com's Answer #91999 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
How many liters of pure acid must be mixed with 20 liters of a 15% acid solution to get 20% mixture?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of pure acid required
\n" ); document.write( ":
\n" ); document.write( "This is to be mixed with 20 liters, therefore:
\n" ); document.write( "The amt of the final mixture will = (x+20)
\n" ); document.write( ":
\n" ); document.write( "Pure acid will be 1.0x
\n" ); document.write( ":
\n" ); document.write( ".15(20) + 1.0x = .20(x+ 20)
\n" ); document.write( ":
\n" ); document.write( "3 + 1x + .20x + 4
\n" ); document.write( ":
\n" ); document.write( "1x - .2x = 4 - 3
\n" ); document.write( ":
\n" ); document.write( ".8x = 1
\n" ); document.write( "x = $\"1%2F.8\"$
\n" ); document.write( "x = 1.25 liters of pure acid to produce a 20% mixture
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( ".15(20) + 1.25 = .20(21.25)
\n" ); document.write( " 3 + 1.25 = 4.25; confirms our solution \n" ); document.write( "

\n" );