document.write( "Question 125584: a long distance runner, runs at an average velocity of 8mph. Two hours after Tanya leaves your house, you leave in your honda and follow the same route. If your average velocity is 40 mph, how long will it be before you catch up with Tanya? How far will you be from your home? \n" ); document.write( "
Algebra.Com's Answer #91995 by ankor@dixie-net.com(22740)\"\" \"About 
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a long distance runner, runs at an average velocity of 8mph. Two hours after Tanya leaves your house, you leave in your honda and follow the same route. If your average velocity is 40 mph, how long will it be before you catch up with Tanya? How far will you be from your home?
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\n" ); document.write( "Let t = time required for you to catch up with T
\n" ); document.write( "Then
\n" ); document.write( "(t+2) = T's travel time when she is caught
\n" ); document.write( ":
\n" ); document.write( "One thing to remember in any of these \"catch-up programs\" is both of you travel
\n" ); document.write( "the same distance, write a simple distance equation from this fact.
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\n" ); document.write( "Distance = speed * time
\n" ); document.write( ":
\n" ); document.write( "Your dist = T's distance
\n" ); document.write( "40t = 8(t+2)
\n" ); document.write( ":
\n" ); document.write( "40t = 8t + 16
\n" ); document.write( ":
\n" ); document.write( "40t - 8t = 16
\n" ); document.write( ":
\n" ); document.write( "32t = 16
\n" ); document.write( "t = \"16%2F32\"
\n" ); document.write( "t = \"1%2F2\" hr for you to catch up
\n" ); document.write( ":
\n" ); document.write( "Find the distance using t = .5 hr for you and 2.5 hr for T
\n" ); document.write( "40 * .5 = 20 mi
\n" ); document.write( "8 * 2.5 = 20 mi also; confirms our solution \n" ); document.write( "
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