document.write( "Question 125495: what is the equation of a horizontal line that passes through the point at
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\n" ); document.write( "I do not understand this question could someone please help? thank u
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Algebra.Com's Answer #91941 by solver91311(24713)\"\" \"About 
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The essential characteristic of a horizontal line is that the y-coordinates of every point on the line are equal, and the x-coordinates are the set of all real numbers.\r
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\n" ); document.write( "\n" ); document.write( "In order for the line to pass through the point (-2,-3), every point on the line must have a y coordinate of -3. So the equation is simply \"y=-3\".\r
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\n" ); document.write( "\n" ); document.write( "Another way to look at it is that a horizontal line has a slope of zero, so using the point-slope form of the straight line: \"y-y%5B1%5D=m%28x-x%5B1%5D%29\", you get:\r
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\n" ); document.write( "\n" ); document.write( "\"y-%28-3%29=0%28x-%28-2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3\".
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