document.write( "Question 125496: the area of a rectangular wall of a barn is 96 square feet. its length is 10 feet longer than the width. find the length and width of the wall of the barn. \n" ); document.write( "

Algebra.Com's Answer #91937 by solver91311(24713) $\"\"$ $\"About$

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x is the width, x + 10 is the length. The area is the length times the width or $\"x%28x%2B10%29\"$ and is equal to 96 sq ft.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%28x%2B10%29=96\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B10x=96\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B10x-96=0\"$ \r
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\n" ); document.write( "\n" ); document.write( "Factors of -96 whose sum is +10 are -6 and +16, so:\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%2B16%29%28x-6%29=0\"$ , so $\"x=-16\"$ or $\"x=6\"$ . You'll have a very hard time finding a barn wall with a width of -16 feet, so we can exclude that solution. The width is 6 feet and the lenght is 6 + 10 or 16 feet. That's a very tall, skinny barn or a long but very short barn. \n" ); document.write( "

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