document.write( "Question 125486: The sum of 4 consecutive integers is one more than the third. Find the integers \n" ); document.write( "
Algebra.Com's Answer #91928 by solver91311(24713)\"\" \"About 
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If the first integer is x, then the second must be x + 1, the third x + 2, and the fourth x + 3. Their sum must then be \"x%2B%28x%2B1%29%2B%28x%2B2%29%2B%28x%2B3%29\". This sum is one more than the third. The third consecutive integer is x + 2, so one more than that is x + 3. Therefore we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%28x%2B1%29%2B%28x%2B2%29%2B%28x%2B3%29=x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Removing the parentheses and collecting terms gets us to:
\n" ); document.write( "\"4x%2B6=x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Add -x to both sides and add -6 to both sides:
\n" ); document.write( "\"3x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by 3
\n" ); document.write( "\"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore the integers are -1, 0, 1, and 2.\r
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\n" ); document.write( "\n" ); document.write( "Check: -1 + 0 + 1 + 2 = 2, so the sum of the integers is 2.
\n" ); document.write( "The third is 1, and one more than that is 2. Answer checks.
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