document.write( "Question 125391: Solve the following systems by addition. \r
\n" ); document.write( "\n" ); document.write( "2x - y = 1\r
\n" ); document.write( "\n" ); document.write( "- 2x + 3y= 5\r
\n" ); document.write( "\n" ); document.write( "please help thank you
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Algebra.Com's Answer #91910 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( " \"-2%2Ax%2B3%2Ay=5\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and -2 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 2 and -2 is -2, we need to multiply both sides of the top equation by -1 and multiply both sides of the bottom equation by -1 like this:
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\n" ); document.write( " \"-1%2A%282%2Ax-1%2Ay%29=%281%29%2A-1\" Multiply the top equation (both sides) by -1
\n" ); document.write( " \"-1%2A%28-2%2Ax%2B3%2Ay%29=%285%29%2A-1\" Multiply the bottom equation (both sides) by -1
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"-2%2Ax%2B1%2Ay=-1\"
\n" ); document.write( " \"2%2Ax-3%2Ay=-5\"
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\n" ); document.write( " Notice how -2 and 2 add to zero (ie \"-2%2B2=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%28-2%2Ax%2B2%2Ax%29%2B%281%2Ay-3%2Ay%29=-1-5\"
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\n" ); document.write( " \"%28-2%2B2%29%2Ax%2B%281-3%29y=-1-5\"
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\n" ); document.write( " \"cross%28-2%2B2%29%2Ax%2B%281-3%29%2Ay=-1-5\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-2%2Ay=-6\"
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\n" ); document.write( " \"y=-6%2F-2\" Divide both sides by \"-2\" to solve for y
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\n" ); document.write( " \"y=3\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"2%2Ax-1%2Ay=1\" to solve for x
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\n" ); document.write( " \"2%2Ax-1%283%29=1\" Plug in \"y=3\"
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\n" ); document.write( " \"2%2Ax-3=1\" Multiply
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\n" ); document.write( " \"2%2Ax=1%2B3\" Subtract \"-3\" from both sides
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\n" ); document.write( " \"2%2Ax=4\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F2%29%282%29%29%2Ax=%284%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out \"2\" on the left side.
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\n" ); document.write( " \"x=2\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=2\", \"y=3\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"2\", \"3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( " \"-2%2Ax%2B3%2Ay=5\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax-1%2Ay=1\" (red) \"-2%2Ax%2B3%2Ay=5\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"2\",\"3\"). This verifies our answer.

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