document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125463>Question 125463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the larger numbers is equal to four times the smaller. The sum of the numbers is 21. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91907 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the larger number = x and the smaller be y.<BR>\n" );
document.write( "Then we have x + y = 21 -------------(1)<BR>\n" );
document.write( "Also given 3 times the larger = 4 times the smaller<BR>\n" );
document.write( "==> 3x = 4y<BR>\n" );
document.write( "==> 3x - 4y = 0<BR>\n" );
document.write( "    4x + 4y = 84  [ 4 times (1)]<BR>\n" );
document.write( "Adding the above 2 equations, 7x = 84<BR>\n" );
document.write( "==> x = 84/7<BR>\n" );
document.write( "==> x = 12<BR>\n" );
document.write( "So 3x = 36<BR>\n" );
document.write( "==> 4y = 36<BR>\n" );
document.write( "==> y = 36/4<BR>\n" );
document.write( "==> y = 9\r<BR>\n" );
document.write( "\n" );
document.write( "Thus the bigger number is 12 and the smaller number is 9.\r<BR>\n" );
document.write( "\n" );
document.write( "good luck!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );