document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125464>Question 125464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not able to figure these out, can anyone help me out? \r<BR>\n" );
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document.write( "Find the equations of the horizontal and vertical asymptotes for the following. Type none if the function does not have an asymptote.\r<BR>\n" );
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document.write( "a) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=2x%2B3%2Fx%2B2 ALIGN=MIDDLE  ALT=\"f%28x%29=2x%2B3%2Fx%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > this is not showing correctly on the preview, it's supossed to be: \"f(x)= 2x+3 OVER x+2\".\r<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "Horizontal:<BR>\n" );
document.write( "Vertical:\r<BR>\n" );
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document.write( "b) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=g%28x%29=5x%2Fx%5E2%2B1 ALIGN=MIDDLE  ALT=\"g%28x%29=5x%2Fx%5E2%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" > this is not showing correctly on the preview, its supossed to be:  \"g(x)= 5x OVER x^2+1\".\r<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "Horizontal:<BR>\n" );
document.write( "Vertical:<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91906 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a) given f(x) = (2x+3)/(x+2)\r<BR>\n" );
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document.write( "To get the vertical asymptote, set the denominator to 0<BR>\n" );
document.write( "==> x+2 = 0<BR>\n" );
document.write( "==> x = -2 is the equation of the vertical asymptote.<BR>\n" );
document.write( "Now divide all the terms of the function by x and set lt x-> infinity.\r<BR>\n" );
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document.write( "==> f(x) = (2 + 3/x)/ (1 + 2/x)<BR>\n" );
document.write( "AS x -> infinity, we have f(x) = 2/1 = 2<BR>\n" );
document.write( "Thus y = 1 is the equation of the horizontal asymptote.\r<BR>\n" );
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document.write( "(b)As x^2 + 1 = 0 does not have a real solution, there is no vertical asymptote.<BR>\n" );
document.write( "Divide each term by x^2 and setting lt x-> 0, we get y = 0<BR>\n" );
document.write( "So y = 0 is the equation of the horizontal asymptote.\r<BR>\n" );
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document.write( "good luck!!!<BR>\n" );
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