document.write( "Question 125403This question is from textbook beginning algebra
\n" ); document.write( ": 1/3x + 5/6 = 2/x\r
\n" ); document.write( "\n" ); document.write( "Solve and check solution.\r
\n" ); document.write( "\n" ); document.write( "Please help me step by step on this problem in hopes to gain some insight on what I am not understanding. I am in an excelerated course ... (which is an 8 week course I need to pass in order to get my associates degree) I am in the fourth week and I'm struggling any help is greatly appreciated... Thank you in advance for your time and help.
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Algebra.Com's Answer #91885 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1/3x + 5/6 = 2/x
\n" ); document.write( "Multiply thru by 6x to get:
\n" ); document.write( "--------
\n" ); document.write( "2 + 5x = 12
\n" ); document.write( "5x = 10
\n" ); document.write( "x = 2
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\n" ); document.write( "Check:
\n" ); document.write( "1/(6) + 5/6 = 2/2
\n" ); document.write( "1 = 1
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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