document.write( "Question 125268: Find the unknown qanity for an account that earns simple annual interest.\r
\n" ); document.write( "\n" ); document.write( "A = $579, P = $300,
\n" ); document.write( " r = 6.2%, t=___\r
\n" ); document.write( "\n" ); document.write( "Any help with this equation would be Greatly appreciated.
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Algebra.Com's Answer #91846 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"A+=+P%281+%2B+r%2At%29\"
\n" ); document.write( "\"579+=+300%281+%2B+.062%2At%29\"
\n" ); document.write( "\"579+=+300+%2B+18.6t\"
\n" ); document.write( "\"18.6t+=+279\"
\n" ); document.write( "\"t+=+15\" years answer
\n" ); document.write( "At the end of each year with simple interest I have:
\n" ); document.write( "1st year: $300 + 1*.062*300
\n" ); document.write( "2nd year $300 + 2*.062*300
\n" ); document.write( "3rd year $300 + 3*.062*300
\n" ); document.write( "etc.
\n" ); document.write( "So the general formula is
\n" ); document.write( "A = P(1 + rt)
\n" ); document.write( "check answer
\n" ); document.write( "\"579+=+300%281+%2B+.062%2At%29\"
\n" ); document.write( "\"579+=+300+%2B+300%2A.062%2A15\"
\n" ); document.write( "\"579+=+300+%2B279\"
\n" ); document.write( "\"579+=+579\"
\n" ); document.write( "OK
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