document.write( "Question 125270: Is this correct? \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. Multiply (x-2)(x+2); answer: x^2+4?
\n" ); document.write( "2. x^4-2x^3+5x^2+10x+12 for value of x=2 ; answer: 52?
\n" ); document.write( "3. A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200ml of a 35% acid solution? ; answer: 120 ml of 25% and 80 ml of 50%? \r
\n" ); document.write( "\n" ); document.write( "I appreciate the help; hopefully I got them right. \n" ); document.write( "
Algebra.Com's Answer #91831 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
1) (X-2)(X=2)=X^2-4 ANSWER.
\n" ); document.write( "2) X^4-2X^3+5X^2+10X+12 WHEN X=2 THEN
\n" ); document.write( "2^4-2*2^3+5*2^2+10*2+12
\n" ); document.write( "16-2*8+5*4+20+12
\n" ); document.write( "16-16+20+20+12=53 ANSWER.
\n" ); document.write( "3) .5X+.25(200-X)=.35*200
\n" ); document.write( ".5X+50-.25X=70
\n" ); document.write( ".25X=70-50
\n" ); document.write( ".25X=20
\n" ); document.write( "X=20/.25
\n" ); document.write( "X=80 ML OF 50% ACID IS REQUIRED.
\n" ); document.write( "200-80=120 ML OF 25% SOLUTION IS REQUIRED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".5*80+.25*120=70
\n" ); document.write( "40+30=70
\n" ); document.write( "70=70\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );