document.write( "Question 125288: How many gallons of an 80% alcohol solution must be mixed with 30 gallons of a 22% solution to obtain a solution that is 70% alcohol? \n" ); document.write( "
Algebra.Com's Answer #91829 by checkley71(8403)\"\" \"About 
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.8X+.22*30=.7(X+30)
\n" ); document.write( ".8X+6.6=.7X+21
\n" ); document.write( ".8X-.7X=21-6.6
\n" ); document.write( ".1X=14.4
\n" ); document.write( "X=14.4/.1
\n" ); document.write( "X=144 GALLONS OF 80% SOLUTION IS REQUIRED.
\n" ); document.write( "PROOF
\n" ); document.write( ".8*144+.22*30=.7(144+30)
\n" ); document.write( "115.2+6.6=121.8
\n" ); document.write( "121.8=121.8
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