document.write( "Question 125288: How many gallons of an 80% alcohol solution must be mixed with 30 gallons of a 22% solution to obtain a solution that is 70% alcohol? \n" ); document.write( "
Algebra.Com's Answer #91829 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .8X+.22*30=.7(X+30) \n" ); document.write( ".8X+6.6=.7X+21 \n" ); document.write( ".8X-.7X=21-6.6 \n" ); document.write( ".1X=14.4 \n" ); document.write( "X=14.4/.1 \n" ); document.write( "X=144 GALLONS OF 80% SOLUTION IS REQUIRED. \n" ); document.write( "PROOF \n" ); document.write( ".8*144+.22*30=.7(144+30) \n" ); document.write( "115.2+6.6=121.8 \n" ); document.write( "121.8=121.8 \n" ); document.write( " \n" ); document.write( " |