document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125290>Question 125290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi. Can I have some help with functions?\r<BR>\n" );
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document.write( "Evaluate the function at the indicated values.\r<BR>\n" );
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document.write( "h(t)=t+1/t;\r<BR>\n" );
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document.write( "h(1),h(-1),h(2),h(1/2),h(x),h(1/x)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91828 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You certainly can.  When you change h(t) to h(1), you are replacing every t with 1.  So h(1)=(1)+1/(1).  Since division comes before addition in the order of operations, do the division first (assuming you typed this in exactly how it appears).  So it is 1+1=2.  So h(1)=2.<BR>\n" );
document.write( "h(-1)=(-1)+1/(-1)=-1+-1=-2<BR>\n" );
document.write( "Now I'll skip the middle ones for you to do, but I'll do the last since it is most tricky.  Try it yourself and check your answer after.\r<BR>\n" );
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document.write( "h(1/x)=(1/x)+1/(1/x) = (1/x)+x </SPAN>\n" );
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