document.write( "Question 125272: A chemist wants to mix a 60% saline solution with 20 liters of a 45% saline solution to obtain a 55% saline solution. How much of the 60% solution should she use? \n" ); document.write( "
Algebra.Com's Answer #91819 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
.6X+.45*20=.55(X+20)
\n" ); document.write( ".6X+9=.55X+11
\n" ); document.write( ".6X-.55X=11-9
\n" ); document.write( ".05X=2
\n" ); document.write( "X=2/.05
\n" ); document.write( "X=40 LITERS OF 60% SOLUTION IS NEEDED.
\n" ); document.write( "PROOF.
\n" ); document.write( ".6*40+.45*20=.55(40+20)
\n" ); document.write( "24+9=.55*60
\n" ); document.write( "33=33\r
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