document.write( "Question 125272: A chemist wants to mix a 60% saline solution with 20 liters of a 45% saline solution to obtain a 55% saline solution. How much of the 60% solution should she use? \n" ); document.write( "
Algebra.Com's Answer #91819 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .6X+.45*20=.55(X+20) \n" ); document.write( ".6X+9=.55X+11 \n" ); document.write( ".6X-.55X=11-9 \n" ); document.write( ".05X=2 \n" ); document.write( "X=2/.05 \n" ); document.write( "X=40 LITERS OF 60% SOLUTION IS NEEDED. \n" ); document.write( "PROOF. \n" ); document.write( ".6*40+.45*20=.55(40+20) \n" ); document.write( "24+9=.55*60 \n" ); document.write( "33=33\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |