document.write( "Question 125279: Hello can someone please try and solve these problems, i would greatly appericiate it!!
\n" ); document.write( "J. Rivera. \r
\n" ); document.write( "\n" ); document.write( "1) State the domain of the following:\r
\n" ); document.write( "\n" ); document.write( "a)\"g%28x%29=sqrt+sign+x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "b)\"g%28x%29=2x%2B1%2Fx-3+\"
\n" ); document.write( "2x+1 OVER x-s
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\n" ); document.write( "\n" ); document.write( "c) h(x)=3x^2+5x-3 \r
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\n" ); document.write( "\n" ); document.write( "d) l(x)-2x+3 \r
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\n" ); document.write( "\n" ); document.write( "e) m(x)=3/x^2-7 m \"3 OVER x^2-7\" \r
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Algebra.Com's Answer #91818 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
1) State the domain of the following:\r
\n" ); document.write( "\n" ); document.write( "a)\"g%28x%29=sqrt+%28+x%2B4%29\"\r
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\n" ); document.write( "you know that \"x%2B4\" has to be positive
\n" ); document.write( "Therefore if \"x+%3C+-4\" the result would be a \"negative\"\"+number\" inside the radical which is \"not\" \"allowed\". \r
\n" ); document.write( "\n" ); document.write( "so, the domain would be \"-4\" to \"%2B+infinity\" (0 is allowed)
\n" ); document.write( "Interval notation [\"-4\", \"infinity\") \r
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\n" ); document.write( "\n" ); document.write( "b)\"g%28x%29=2x%2B1%2Fx-3+\"\r
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\n" ); document.write( "denominator cannot be equal to \"0\"; so, if \"x-3=0\" we will have to divide by \"0\" which doesn't make a sense.
\n" ); document.write( "if \"x-3=0\" ...then \"x=3\"\r
\n" ); document.write( "\n" ); document.write( "the domain would be \"+-+infinity\" to \"3\"and from \"3\" to \"%2B+infinity\" \r
\n" ); document.write( "\n" ); document.write( "Interval notation (\"+-+infinity\", \"3\"] U (\"+3\", \"infinity\"] \r
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\n" ); document.write( "\n" ); document.write( "c) h(x)=3x^2+5x-3 \r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( " first find square roots
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"3%2Ax%5E2%2B5%2Ax-3=0\" ( notice \"a=3\", \"b=5\", and \"c=-3\")
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A3%2A-3+%29%29%2F%282%2A3%29\" Plug in a=3, b=5, and c=-3
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+25-4%2A3%2A-3+%29%29%2F%282%2A3%29\" Square 5 to get 25
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+25%2B36+%29%29%2F%282%2A3%29\" Multiply \"-4%2A-3%2A3\" to get \"36\"
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+61+%29%29%2F%282%2A3%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%2861%29%29%2F%282%2A3%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%2861%29%29%2F6\" Multiply 2 and 3 to get 6
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%28-5+%2B+sqrt%2861%29%29%2F6\" or \"x+=+%28-5+-+sqrt%2861%29%29%2F6\"
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\n" ); document.write( " Now break up the fraction
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\n" ); document.write( " \"x=-5%2F6%2Bsqrt%2861%29%2F6\" or \"x=-5%2F6-sqrt%2861%29%2F6\"
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\n" ); document.write( " Simplify
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\n" ); document.write( " \"x=-5%2F6%2Bsqrt%2861%29%2F6\" or \"x=-5%2F6-sqrt%2861%29%2F6\"
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\n" ); document.write( " So the solutions are:
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\n" ); document.write( " \"x=-5%2F6%2Bsqrt%2861%29%2F6\" or \"x=-5%2F6-sqrt%2861%29%2F6\"
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\n" ); document.write( "\n" ); document.write( "the domain would be \"+-+infinity\" to \".47\"and from \".47\" to \"%2B+infinity\" \r
\n" ); document.write( "\n" ); document.write( "Interval notation (\"+-+infinity\", \".47\"] U [\"+.47\", \"infinity\") \r
\n" ); document.write( "\n" ); document.write( "or
\n" ); document.write( "the domain would be \"+-+infinity\" to \"-2.14\"and from \"-2.14\" to \"%2B+infinity\" \r
\n" ); document.write( "\n" ); document.write( "Interval notation (\"+-+infinity\", \"-2.14\"] U [\"+-2.14\", \"infinity\") \r
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\n" ); document.write( "\n" ); document.write( "d) l(x)= -2x+3
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\n" ); document.write( "Answer:
\n" ); document.write( "(\"+-+infinity\", \"+infinity\") \r
\n" ); document.write( "\n" ); document.write( "e) m(x)=3/x^2-7 m \"3 OVER x^2-7\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-7\" cannot be equal to \"0\"; \"x%5E2-7=0\" ...\"x%5E2=7\" ......\"x=sqrt%287%29+\" \r
\n" ); document.write( "\n" ); document.write( "the domain would be \"+-+infinity\" to \"+sqrt%287%29\"and from \"+sqrt%287%29\" to \"%2B+infinity\" \r
\n" ); document.write( "\n" ); document.write( "Interval notation (\"+-+infinity\", \"+sqrt%287%29\"] U [\"+sqrt%287%29\", \"infinity\")
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