document.write( "Question 125252:
\n" ); document.write( "5) Find the equations of the horizontal and vertical asymptotes for the following. Type none if the function does not have an asymptote.\r
\n" ); document.write( "\n" ); document.write( "a) f (x)= 2x+3/x+2 \r
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\n" ); document.write( "\n" ); document.write( "b) g (x) = 5x/x^+1\r
\n" ); document.write( "\n" ); document.write( "Answer:
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Algebra.Com's Answer #91806 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"y=%282x%2B3%29%2F%28x%2B2%29%29\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "Looking at the numerator \"2x%2B3\", we can see that the degree is \"1\" since the highest exponent of the numerator is \"1\". For the denominator \"x%2B2\", we can see that the degree is \"1\" since the highest exponent of the denominator is \"1\".\r
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\n" ); document.write( "\n" ); document.write( " Horizontal Asymptote: \r
\n" ); document.write( "\n" ); document.write( "Since the degree of the numerator and the denominator are the same, we can find the horizontal asymptote using this procedure:\r
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\n" ); document.write( "\n" ); document.write( "To find the horizontal aysmptote, first we need to find the leading coefficients of the numerator and the denominator.\r
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\n" ); document.write( "\n" ); document.write( "Looking at the numerator \"2x%2B3\", the leading coefficient is \"2\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the denominator \"x%2B2\", the leading coefficient is \"1\"\r
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\n" ); document.write( "\n" ); document.write( "So the horizontal aysmptote is the ratio of the leading coefficients. In other words, simply divide \"2\" by \"1\" to get \"%282%29%2F%281%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=2\"\r
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\n" ); document.write( "\n" ); document.write( " Vertical Asymptote: \r
\n" ); document.write( "\n" ); document.write( "To find the vertical aysmptote, just set the denominator equal to zero and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=0\" Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=0-2\"Subtract 2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "So the vertical asymptote is \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=%282x%2B3%29%2F%28x%2B2%29\", we can visually verify our answers:\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%282x%2B3%29%2F%28x%2B2%29%29\" with the horizontal asymptote \"y=2\" (blue line) and the vertical asymptote \"x=-2\" (green line)\r
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\n" ); document.write( "\n" ); document.write( "b)\r
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\n" ); document.write( "\n" ); document.write( "\"y=%285x%29%2F%28x%5E2%2B1%29%29\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "Looking at the numerator \"5x\", we can see that the degree is \"1\" since the highest exponent of the numerator is \"1\". For the denominator \"x%5E2%2B1\", we can see that the degree is \"2\" since the highest exponent of the denominator is \"2\".\r
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\n" ); document.write( "\n" ); document.write( " Horizontal Asymptote: \r
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\n" ); document.write( "\n" ); document.write( "Since the degree of the numerator (which is \"1\") is less than the degree of the denominator (which is \"2\"), the horizontal asymptote is always \"y=0\"\r
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\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=0\"\r
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\n" ); document.write( "\n" ); document.write( " Vertical Asymptote: \r
\n" ); document.write( "\n" ); document.write( "To find the vertical aysmptote, just set the denominator equal to zero and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B1=0\" Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=0-1\"Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=-1\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%28-1%29\" Take the square root of both sides\r
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\n" ); document.write( "Since you cannot take the square root of a negative number, the answer is not a real number. So in this case, there are no vertical asymptotes. \r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=%285x%29%2F%28x%5E2%2B1%29\", we can visually verify our answers:\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%285x%29%2F%28x%5E2%2B1%29%29\" with the horizontal asymptote \"y=0\" (blue line) . Notice how there are no vertical asymptotes
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