document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125248>Question 125248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> AN HEBALIST HAS 30 OZ OF HERBS COSTING $2 PER OUNCE.  HOW MANY OUNCES OF HERBS COSTING $1 PER OUNCE SHOULD BE MIXED WITH THE 30 OZ TO PRODUCE A MIXTURE COSTING $1.60 PER OUNCE? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91804 by </B><A HREF=/tutors/aboutme.mpl?userid=dolly><B>dolly(163)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dolly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x ounces of herbs costing $1 be added.<BR>\n" );
document.write( "Then 30(2) + (x)(1) = (30+x)(1.6)<BR>\n" );
document.write( "==>   60 + x = 48 + 1.6x<BR>\n" );
document.write( "==> 60 - 48 = 1.6x - x<BR>\n" );
document.write( "==>  12 = 0.6x<BR>\n" );
document.write( "==> 12/0.6 = x<BR>\n" );
document.write( "==> x = 20\r<BR>\n" );
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document.write( "Thus 20 ounces cosing $1 need to be added,\r<BR>\n" );
document.write( "\n" );
document.write( "Good luck </SPAN>\n" );
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