document.write( "Question 125244: Matthew invested some of his money at 6.5% and $450 less at 8%. His total annual intrest income is $167. How much did Matthew invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #91800 by dolly(163)\"\" \"About 
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Let the money invested at 6.5% be x
\n" ); document.write( "Then money invested at 8% = (x-450)
\n" ); document.write( "His annual interest = $ 167
\n" ); document.write( "==> x(0.065) + (x-450)(0.08) = 167
\n" ); document.write( "==> x(0.145) - 36 = 167
\n" ); document.write( "==> x(0.145) = 36 + 167
\n" ); document.write( "==> x(0.145) = 203
\n" ); document.write( "==> x = 203/0.145
\n" ); document.write( "==> x = 1400
\n" ); document.write( "Thus the money invested at 8% = 1400 - 450
\n" ); document.write( " = $ 950\r
\n" ); document.write( "\n" ); document.write( "good luck
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