document.write( "Question 125244: Matthew invested some of his money at 6.5% and $450 less at 8%. His total annual intrest income is $167. How much did Matthew invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #91800 by dolly(163)![]() ![]() ![]() You can put this solution on YOUR website! Let the money invested at 6.5% be x \n" ); document.write( "Then money invested at 8% = (x-450) \n" ); document.write( "His annual interest = $ 167 \n" ); document.write( "==> x(0.065) + (x-450)(0.08) = 167 \n" ); document.write( "==> x(0.145) - 36 = 167 \n" ); document.write( "==> x(0.145) = 36 + 167 \n" ); document.write( "==> x(0.145) = 203 \n" ); document.write( "==> x = 203/0.145 \n" ); document.write( "==> x = 1400 \n" ); document.write( "Thus the money invested at 8% = 1400 - 450 \n" ); document.write( " = $ 950\r \n" ); document.write( "\n" ); document.write( "good luck \n" ); document.write( " \n" ); document.write( " |