document.write( "Question 125214:  I dont understand this:\r
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document.write( "Kendra invested $850, part of it at 9% and part of it at 12%. If her interest for one year was $81 how much did she invest at each rate? \n" );
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| Algebra.Com's Answer #91789 by checkley71(8403)      You can put this solution on YOUR website! .12X+.09(850-X)=81 \n" ); document.write( ".12X+76.5-.09X=81 \n" ); document.write( ".12X-.09X=81-76.5 \n" ); document.write( ".03X=4.5 \n" ); document.write( "X=4.5/.03 \n" ); document.write( "X=150 AMOUNRT INVESTED @ 12%. \n" ); document.write( "850-150=700 INVESTED @ 9%. \n" ); document.write( "PROOF \n" ); document.write( ".12*150+.09*700=81 \n" ); document.write( "18+63=81 \n" ); document.write( "81=81 \n" ); document.write( " |