document.write( "Question 125214: I dont understand this:\r
\n" ); document.write( "\n" ); document.write( "Kendra invested $850, part of it at 9% and part of it at 12%. If her interest for one year was $81 how much did she invest at each rate?
\n" ); document.write( "

Algebra.Com's Answer #91789 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
.12X+.09(850-X)=81
\n" ); document.write( ".12X+76.5-.09X=81
\n" ); document.write( ".12X-.09X=81-76.5
\n" ); document.write( ".03X=4.5
\n" ); document.write( "X=4.5/.03
\n" ); document.write( "X=150 AMOUNRT INVESTED @ 12%.
\n" ); document.write( "850-150=700 INVESTED @ 9%.
\n" ); document.write( "PROOF
\n" ); document.write( ".12*150+.09*700=81
\n" ); document.write( "18+63=81
\n" ); document.write( "81=81
\n" ); document.write( "
\n" );