document.write( "Question 125230: A 60 ft. pipe is divided into three peices. One peice is twice a long as the shortest peice, and the third peice is 4 feet less than five times the shortest peice. Find the length of the shortest peice. \n" ); document.write( "

Algebra.Com's Answer #91781 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"x\"$ = the shortest piece
\n" ); document.write( "Another piece is $\"2x\"$
\n" ); document.write( "The 3rd piece is $\"5x+-+4\"$
\n" ); document.write( " $\"x+%2B+2x+%2B+5x+-+4+=+60\"$
\n" ); document.write( " $\"8x+-+4+=+60\"$
\n" ); document.write( " $\"8x+=+64\"$
\n" ); document.write( " $\"x+=+8\"$ ft
\n" ); document.write( "check
\n" ); document.write( " $\"x+%2B+2x+%2B+5x+-+4+=+60\"$
\n" ); document.write( " $\"8+%2B+2%2A8+%2B+5%2A8+-+4+=+60\"$
\n" ); document.write( " $\"8+%2B+16+%2B+40+-+4+=+60\"$
\n" ); document.write( " $\"60+=+60\"$
\n" ); document.write( "OK \n" ); document.write( "

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