document.write( "Question 125230: A 60 ft. pipe is divided into three peices. One peice is twice a long as the shortest peice, and the third peice is 4 feet less than five times the shortest peice. Find the length of the shortest peice. \n" ); document.write( "
Algebra.Com's Answer #91780 by checkley71(8403)\"\" \"About 
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LET X BE THE SHORTEST PIECE.
\n" ); document.write( "2X IS THE NEXT PIECE.
\n" ); document.write( "5X-4 IS THE LONGEST PIECE.
\n" ); document.write( "X+2X+5X-4=60
\n" ); document.write( "8X=60+4
\n" ); document.write( "8X=64
\n" ); document.write( "X=64/8
\n" ); document.write( "X=8 FEET IS THE LENGTH OF THE SHORTEST PIECE.\r
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