document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19110>Question 19110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I Need help on this one. Some corn costing 60 cents per kilogram is added to 50 kilograms of oats costing 90 cents per kilogram to make an animal feed costing 75 cents per kilogram. How many Kilograms of corn should be added.\r<BR>\n" );
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document.write( "So far i have .60(x+50)+.50(90)=.75+x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9178 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60t+50(90-t)=90(75)<BR>\n" );
document.write( "60t+4500-50t=6750 (subtract both sides by 3750 and collect like terms)<BR>\n" );
document.write( "10t=2250<BR>\n" );
document.write( "t=225\r<BR>\n" );
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document.write( "I am guessing 225kg of corn </SPAN>\n" );
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