document.write( "Question 125220:
\n" ); document.write( "looked like a rectangle is 300 cm^2. the difference between length and width is 13 cm. find the lenght of the diagonal
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Algebra.Com's Answer #91771 by checkley71(8403)\"\" \"About 
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L=W+13
\n" ); document.write( "300=W(W+13)
\n" ); document.write( "300=W^2+13W
\n" ); document.write( "W^2+13W-300=0
\n" ); document.write( "(W-12)(W+25)
\n" ); document.write( "W-12=0
\n" ); document.write( "W=12cmNSWER FOR THE WIDTH.
\n" ); document.write( "L=12+13=25cm R THE LENGTH.
\n" ); document.write( "THE DIAGONAL IS C
\n" ); document.write( "A^2+B^2=C^2
\n" ); document.write( "12^2+25^2C^2
\n" ); document.write( "144+625=C^2
\n" ); document.write( "769=C^2
\n" ); document.write( "C=SQRT769
\n" ); document.write( "C=27.73cm IS THE LENGTH OF THE DIAGONAL.
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