document.write( "Question 125220:
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document.write( "looked like a rectangle is 300 cm^2. the difference between length and width is 13 cm. find the lenght of the diagonal \n" );
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Algebra.Com's Answer #91771 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=W+13 \n" ); document.write( "300=W(W+13) \n" ); document.write( "300=W^2+13W \n" ); document.write( "W^2+13W-300=0 \n" ); document.write( "(W-12)(W+25) \n" ); document.write( "W-12=0 \n" ); document.write( "W=12cmNSWER FOR THE WIDTH. \n" ); document.write( "L=12+13=25cm R THE LENGTH. \n" ); document.write( "THE DIAGONAL IS C \n" ); document.write( "A^2+B^2=C^2 \n" ); document.write( "12^2+25^2C^2 \n" ); document.write( "144+625=C^2 \n" ); document.write( "769=C^2 \n" ); document.write( "C=SQRT769 \n" ); document.write( "C=27.73cm IS THE LENGTH OF THE DIAGONAL. \n" ); document.write( " \n" ); document.write( " |