document.write( "Question 125190: The equation h= -16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to
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Algebra.Com's Answer #91767 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"h=+-16t%5E2%2B112t\" is your equation for height. Since you are given the height of 180 ft., just replace h with 180 and solve it like any other quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%5E2%2B112t=180\"\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%5E2%2B112t-180=0\"\r
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\n" ); document.write( "\n" ); document.write( "If you divide through by -4, the coefficients become a little more manageable:\r
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\n" ); document.write( "\n" ); document.write( "\"4t%5E2-28t%2B45=0\"\r
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\n" ); document.write( "\n" ); document.write( "You can use the quadratic formula if you don't want to scratch your head over the factorization of this one, but the factors come out to:\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-9%29%282x-5%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"x=9%2F2\" or \"x=5%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the arrow will be 180ft above the ground 2.5 seconds after it is released on the way up, and again at 4.5 seconds on the way down.
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