document.write( "Question 125144This question is from textbook Begining Algebra
\n" ); document.write( ": How many liters of a 60% acid solution must be mixed with a 75% acid solution to get 20 LITER of a 72% solution ? \n" ); document.write( "

Algebra.Com's Answer #91743 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(liters of acid in 60% solution)+(liters of acid in 75% solution)
\n" ); document.write( "divided by (total liters of solution including acid) = 72%
\n" ); document.write( "Let $\"a\"$ = liters of 60% solution to be added
\n" ); document.write( "Let $\"b\"$ = liters of 75% solution to be added
\n" ); document.write( " $\"%28.6a+%2B+.75b%29+%2F+%28a+%2B+b%29+=+.72\"$
\n" ); document.write( "Also given is
\n" ); document.write( " $\"a+%2B+b+=+20\"$
\n" ); document.write( " $\"b+=+20+-+a\"$
\n" ); document.write( " $\"%28.6a+%2B+.75%2820+-+a%29%29+%2F+20+=+.72\"$
\n" ); document.write( " $\"%28.6a+%2B+15+-+.75a%29+%2F+20+=+.72\"$
\n" ); document.write( " $\"-+.15a+=+20%2A.72+-+15\"$
\n" ); document.write( " $\"-+.15a+=+14.4+-+15\"$
\n" ); document.write( " $\"-+.15a+=+-.6\"$
\n" ); document.write( " $\"a+=+4\"$ liters
\n" ); document.write( " $\"a+%2B+b+=+20\"$
\n" ); document.write( " $\"b+=+20+-+4\"$
\n" ); document.write( " $\"b+=+16\"$ liters
\n" ); document.write( "check
\n" ); document.write( " $\"%28.6a+%2B+.75b%29+%2F+%28a+%2B+b%29+=+.72\"$
\n" ); document.write( " $\".6%2A4+%2B+.75%2A16%29+%2F+20+=+.72\"$
\n" ); document.write( " $\"%282.4+%2B+12%29+%2F+20+=+.72\"$
\n" ); document.write( " $\"14.4+%2F+20+=+.72\"$
\n" ); document.write( " $\".72+=+.72\"$
\n" ); document.write( "OK \n" ); document.write( "

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