document.write( "Question 124875: Smith bicycled 45 miles goin east from Durango and Jones bicycled 70 miles. Jones averaged 5 miles per hou more than Smith, and his trip took on-half hour longer than Smith's. How fast was each one traveling? \n" ); document.write( "
Algebra.Com's Answer #91739 by ankor@dixie-net.com(22740)\"\" \"About 
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Smith bicycled 45 miles going east from Durango and Jones bicycled 70 miles. Jones averaged 5 miles per hour more than Smith, and his trip took on-half hour longer than Smith's. How fast was each one traveling?
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\n" ); document.write( "Let s = Smith's speed
\n" ); document.write( "It says,\"Jones averaged 5 miles per hour more than Smith,\" therefore:
\n" ); document.write( "(s+5) = Jones' speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = \"distance%2Fspeed\"
\n" ); document.write( "Smiths time = Jones time - half an hour
\n" ); document.write( "\"45%2Fs\" + \"70%2F%28%28s%2B5%29%29+-+1%2F2\"
\n" ); document.write( "Multiply equation by 2s(s+5) to get rid of the denominators
\n" ); document.write( "2s(s+5)*\"45%2Fs\" + 2s(s+5)*\"70%2F%28%28s%2B5%29%29+-+2s%28s%2B5%29%2A1%2F2\"
\n" ); document.write( ":
\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "2(s+5)*45 = 2s*70 - s(s+5)
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\n" ); document.write( "90s + 450 = 140s - s^2 - 5s
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\n" ); document.write( "s^2 + 5s + 90s - 140s + 450 = 0
\n" ); document.write( ":
\n" ); document.write( "s^2 - 45s + 450 = 0; Arranged as a quadratic equation
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\n" ); document.write( "This factors to
\n" ); document.write( "(s - 15) (s - 30) = 0
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\n" ); document.write( "s = 15, or s = 30;
\n" ); document.write( "Check and you will see that either solution will work in the original equation
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\n" ); document.write( "Probably s = 15 is more reasonable\r
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