document.write( "Question 124875: Smith bicycled 45 miles goin east from Durango and Jones bicycled 70 miles. Jones averaged 5 miles per hou more than Smith, and his trip took on-half hour longer than Smith's. How fast was each one traveling? \n" ); document.write( "
Algebra.Com's Answer #91739 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Smith bicycled 45 miles going east from Durango and Jones bicycled 70 miles. Jones averaged 5 miles per hour more than Smith, and his trip took on-half hour longer than Smith's. How fast was each one traveling? \n" ); document.write( ": \n" ); document.write( "Let s = Smith's speed \n" ); document.write( "It says,\"Jones averaged 5 miles per hour more than Smith,\" therefore: \n" ); document.write( "(s+5) = Jones' speed \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( "Smiths time = Jones time - half an hour \n" ); document.write( " \n" ); document.write( "Multiply equation by 2s(s+5) to get rid of the denominators \n" ); document.write( "2s(s+5)* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators and you have: \n" ); document.write( "2(s+5)*45 = 2s*70 - s(s+5) \n" ); document.write( ": \n" ); document.write( "90s + 450 = 140s - s^2 - 5s \n" ); document.write( ": \n" ); document.write( "s^2 + 5s + 90s - 140s + 450 = 0 \n" ); document.write( ": \n" ); document.write( "s^2 - 45s + 450 = 0; Arranged as a quadratic equation \n" ); document.write( ": \n" ); document.write( "This factors to \n" ); document.write( "(s - 15) (s - 30) = 0 \n" ); document.write( ": \n" ); document.write( "s = 15, or s = 30; \n" ); document.write( "Check and you will see that either solution will work in the original equation \n" ); document.write( ": \n" ); document.write( "Probably s = 15 is more reasonable\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |