document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19106>Question 19106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation.\r<BR>\n" );
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document.write( "1/2 x + 1/3 x = 7\r<BR>\n" );
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document.write( "This is what I had tried, but I can't figure out what to do halfway through.\r<BR>\n" );
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document.write( "I multiplied everything by 6; the common denominator.<BR>\n" );
document.write( "6(1/2)x + 6(1/3)x = (7)6\r<BR>\n" );
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document.write( "And then I got:<BR>\n" );
document.write( "3x + 2x = 42\r<BR>\n" );
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document.write( "I subtracted 2x from 2x and then subtracted it from 42.\r<BR>\n" );
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document.write( "3x + 2x = 42 - 2x <BR>\n" );
document.write( "   - 2x\r<BR>\n" );
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document.write( "This is where I get stuck.<BR>\n" );
document.write( "3x = 40x\r<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9173 by </B><A HREF=/tutors/aboutme.mpl?userid=jakegfan><B>jakegfan(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jakegfan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+2x=42\r<BR>\n" );
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document.write( "1. 3x+2x are like terms so add them together<BR>\n" );
document.write( "2. So you will have 5x=42 <BR>\n" );
document.write( "3. Take 42 and divide by 5<BR>\n" );
document.write( "4. That will be your answer </SPAN>\n" );
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