document.write( "Question 125116: Smith bicycled 45 miles going east from Dallas, and Jones bicycled 70 miles. Jones avgd 5 miles per hour more than Smith and his trip took one-half hour longer than Smiths. How fast was each one traveling? \n" ); document.write( "
Algebra.Com's Answer #91726 by stanbon(75887)\"\" \"About 
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Smith bicycled 45 miles going east from Dallas, and Jones bicycled 70 miles. Jones avgd 5 miles per hour more than Smith and his trip took one-half hour longer than Smiths. How fast was each one traveling?
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\n" ); document.write( "Smith DATA:
\n" ); document.write( "Distance = 45 miles ; rate = x mph ; time = d/r = 45/x hrs.
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\n" ); document.write( "Jones DATA:
\n" ); document.write( "Distance = 70 miles ; rate = x+5 mph ; time = d/r = 70/(x+5) hrs.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Jones time - Smith time = 1/2)
\n" ); document.write( "70/(x+5) - 45/x = 1/2
\n" ); document.write( "Multiply thru by 2x(x+5) to get:
\n" ); document.write( "70*2x - 45*2(x+5) = x(x+5)
\n" ); document.write( "140x - 90x+450 = x^2+5x
\n" ); document.write( "x^2-45x-450 = 0
\n" ); document.write( "(x-15)(x-30) = 0
\n" ); document.write( "x = 15 or x = 30
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\n" ); document.write( "Reasonable answer for bicyclists:
\n" ); document.write( "Smith rate = 15 mph
\n" ); document.write( "Jones rate = 20 mph
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\n" ); document.write( "If you like x=30
\n" ); document.write( "Smith rate = 30 mph
\n" ); document.write( "Jones rate = 35 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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