document.write( "Question 125089: There were 166 paid admissions to a game. The price was $2.00 for aduls and $0.75 for children. The amount taken in was $293.25. How many adults and how many children attended? \n" ); document.write( "
Algebra.Com's Answer #91706 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! A+C=166 OR A=166-C \n" ); document.write( "2A+.75C=293.25 NOW REPLACE A WITH (166-C) & SOLVE FOR C. \n" ); document.write( "2(166-C)+.75C=293.25 \n" ); document.write( "332-2C+.75C=293.25 \n" ); document.write( "-1.25C=293.25-332 \n" ); document.write( "-1.25C=-38.75 \n" ); document.write( "C=-38.75/-1.25 \n" ); document.write( "C=31 THE NUMBER OF CHILDREN. \n" ); document.write( "166-31=135 THE NUMBER OF ADULTS. \n" ); document.write( "PROOF \n" ); document.write( "2*135+.75*31=293.25 \n" ); document.write( "270+23.25=293.25 \n" ); document.write( "293.25=293.25\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |