document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125070>Question 125070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this problem.<BR>\n" );
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document.write( "M (2,4 ) is the midpoint of RS.  If S has coordinates (5,0 ) find the distance from R to S. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91696 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE DISTANCE BETWEEN X=5 & X=2 IS 5-2=3.<BR>\n" );
document.write( "SO THE DISTANCE BETWEEN M & R IS ALSO 3 OR 2-3=-1 THE X COORDINATE FOR THE R POINT.<BR>\n" );
document.write( "THE DISTANCE BETWEEN Y=0 & Y=4 IS 4-0=4.<BR>\n" );
document.write( "SO THE DISTANCE BETWEEN M & R IS ALSO 4 0R 4+4=8 THE Y COORDINATE FOR THE R POINT.<BR>\n" );
document.write( "THUS WE HAVE R=(-1,8)<BR>\n" );
document.write( "THE DISTANCE BETWEEN (-1,8) & (5,0) IS<BR>\n" );
document.write( "5+1=6 FOR THE X AXIS.<BR>\n" );
document.write( "8-0=8 FOR THE Y AXIS.<BR>\n" );
document.write( "SO WE HAVE A RIGHT TRIANGLE WITH SIDES EQUAL TO 6 & 8.<BR>\n" );
document.write( "NOW WE FIND THE HYPOTENUSE (DISTANCE BETWEEN R&S).<BR>\n" );
document.write( "6*2+8*2=RS^2<BR>\n" );
document.write( "36+64=RS^2<BR>\n" );
document.write( "100=RS^2<BR>\n" );
document.write( "RS=SQRT100<BR>\n" );
document.write( "RS=10 ANSWER FOR THE DISTANCE BETWEEN R & S.<BR>\n" );
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