document.write( "Question 125050: A backyard has dimensions 3 4/5 yards by 1 1/2 yards.
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Algebra.Com's Answer #91673 by edjones(8007)\"\" \"About 
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L*W=A
\n" ); document.write( "3 4/5=19/5
\n" ); document.write( "1 1/2=3/2
\n" ); document.write( "19/5* 3/2
\n" ); document.write( "=57/10
\n" ); document.write( "=5.7 yds^2
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