document.write( "Question 125058This question is from textbook Structure and Method Book 1
\n" ); document.write( ": 2x=y+1 \n" ); document.write( "
Algebra.Com's Answer #91667 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"2x=y%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+-+y+=+1\"\r
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"2%2Ax-1%2Ay=1\"Start with the given equation
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\n" ); document.write( " \"-1%2Ay=1-2%2Ax\" Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%28-1%29%281-2%2Ax%29\" Multiply both sides by \"-1\"
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\n" ); document.write( " \"y=%28-1%29%281%29%2B%281%29%282%29x%29\" Distribute \"-1\"
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\n" ); document.write( " \"y=-1%2B%282%29x\" Multiply
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\n" ); document.write( " \"y=2%2Ax-1\" Rearrange the terms
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\n" ); document.write( " \"y=2%2Ax-1\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=2\" (the slope) and \"b=-1\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=-4
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\n" ); document.write( " \"y=2%2A%28-4%29-1\"
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\n" ); document.write( " \"y=-8-1\" Multiply
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\n" ); document.write( " \"y=-9\" Add
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\n" ); document.write( " So here's one point (-4,-9)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-3
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\n" ); document.write( " \"y=2%2A%28-3%29-1\"
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\n" ); document.write( " \"y=-6-1\" Multiply
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\n" ); document.write( " \"y=-7\" Add
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\n" ); document.write( " So here's another point (-3,-7). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=2%2Ax-1\" through the points (-4,-9) and (-3,-7)
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\n" ); document.write( " So from the graph we can see that the slope is \"2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,\"-1\")and the x-intercept is (\"0.5\",0) ,or (\"1%2F2\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=-1\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"-1\").
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\n" ); document.write( " So we have one point (0,\"-1\")
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\n" ); document.write( " Now since the slope is \"2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"-1\"), we can go up 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=2%2Ax-1\"
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\n" ); document.write( " So this is the graph of \"y=2%2Ax-1\" through the points (0,-1) and (1,1)
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