document.write( "Question 124999: Jane invested some amount at the rate of 12% simple interest and some other amount at 10% simple interest. She received yearly interest of $130. Randy also invested, and received $4 more as interest. How much amount did each of them invest at differen rates? \n" ); document.write( "
Algebra.Com's Answer #91629 by checkley71(8403)\"\" \"About 
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I apologize. Randy also invested in the same scheme, but he interchanged the amounts invested, and received $4 more as interest. How much amount did each of them invest at different rates?
\n" ); document.write( ".12X+.10Y=130 THE FORMULA FOR JANE'S INVESTMENT.
\n" ); document.write( ".10X+.12Y=134 THE FORMULA FOR RANDY'S INVESTMENT.
\n" ); document.write( "MULTIPLY JANE'S FORMULA BY -10 & RANDY'S BY 12 THEN ADD THEM.
\n" ); document.write( "-1.2X-1Y=-1300
\n" ); document.write( "1.2X+1.44Y=1608
\n" ); document.write( "------------------------------
\n" ); document.write( ".44Y=308
\n" ); document.write( "Y=308/.44
\n" ); document.write( "Y=$700 INVESTED BY JANE @ 10% & BY RANDY @ 12%. ANSWER.
\n" ); document.write( ".12X+.10*700=130
\n" ); document.write( ".12X+70=130
\n" ); document.write( ".12X=130-70
\n" ); document.write( ".12X=60
\n" ); document.write( "X=60/.12
\n" ); document.write( "X=$500 INVESTED BY JANE @ 12% & BY RANDY @ 10%. ANSWER.
\n" ); document.write( "PROOF:
\n" ); document.write( ".10*500+.12*700=134
\n" ); document.write( "50+84=134
\n" ); document.write( "134=134
\n" ); document.write( " \n" ); document.write( "
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