document.write( "Question 124885This question is from textbook
\n" ); document.write( ": Karen invested some money at 9% annual simple interest and $250 more than that amount at 10% interest. If her total yearly interest from both accounts was $101, how much was invested at each rate \n" ); document.write( "

Algebra.Com's Answer #91618 by checkley71(8403) $\"\"$ $\"About$

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.09x+.10(x+250)=101
\n" ); document.write( ".09x+.10x+25=101
\n" ); document.write( ".19x=101-25
\n" ); document.write( ".19x=76
\n" ); document.write( "x=76/.19
\n" ); document.write( "x=$400 invested @ 9%.
\n" ); document.write( "400+250=650 amount invested @ 10%.
\n" ); document.write( "proof.
\n" ); document.write( ".09*400+.10*650=101
\n" ); document.write( "36+65=101
\n" ); document.write( "101=101
\n" ); document.write( " \n" ); document.write( "

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