document.write( "Question 124910: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #91616 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .15X+.14(10,000-X)=1,430 \n" ); document.write( ".15X+1,400-.14X=1,430 \n" ); document.write( ".01X=1,430-1,400 \n" ); document.write( ".01X=30 \n" ); document.write( "X-30/.01 \n" ); document.write( "X=3,000 AMOUNT INVESTED @ 15%. \n" ); document.write( "10,000-3,000=7,000 AMOUNT INVESTED @ 14%. \n" ); document.write( "PROOF: \n" ); document.write( ".15*3,000+.14*7,000=1,430 \n" ); document.write( "450+980=1,430 \n" ); document.write( "1,430=1,430 \n" ); document.write( " |