document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124980>Question 124980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A is 20 years older than B. He is also 6 times as old as B. find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91612 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X represent the age of A. And let Y represent the age of B. <BR>\n" );
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document.write( "The statement that A is 20 years older than B means that to equal B's age you have to subtract 20<BR>\n" );
document.write( "from A's age. Taking 20 away from A's age is represented by the expression X - 20. This will<BR>\n" );
document.write( "be equal to Y. In equation form this equality is written as:<BR>\n" );
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document.write( "X - 20 = Y<BR>\n" );
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document.write( "The problem also tells you that A's age (X) is equal to 6 times B's age (Y). In equation form<BR>\n" );
document.write( "this is:<BR>\n" );
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document.write( "X = 6Y<BR>\n" );
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document.write( "But from the first equation we know that X - 20 is the same as Y. So, in the second equation <BR>\n" );
document.write( "we can replace that Y with X - 20. When we do that the second equation becomes:<BR>\n" );
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document.write( "X = 6(X - 20)<BR>\n" );
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document.write( "Multiply out the right side by multiplying each of the terms inside the parentheses <BR>\n" );
document.write( "by 6. When you do this multiplication this becomes:<BR>\n" );
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document.write( "X = 6X - 120<BR>\n" );
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document.write( "You can get all the terms containing X to one side of this equation by getting rid of <BR>\n" );
document.write( "the 6X on the right side. To do this, just subtract 6X from both sides of the equation. <BR>\n" );
document.write( "Subtracting 6X from the right side eliminates the 6X on that side. Subtracting 6X from<BR>\n" );
document.write( "the X on the left side results in that side becoming -5X. So by subtracting 6X from both<BR>\n" );
document.write( "sides changes the equation to:<BR>\n" );
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document.write( "-5X = -120<BR>\n" );
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document.write( "To solve for that equation you divide both sides of this equation by -5 to get:<BR>\n" );
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document.write( "X = -120/-5 = 24<BR>\n" );
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document.write( "This means that A is 24 years old. Since A is 20 years older than B, then B must be 4 years old.<BR>\n" );
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document.write( "And you can also see that at age 24 A is 6 times older than B who is 4 years old.<BR>\n" );
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document.write( "The answers we got check out.<BR>\n" );
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document.write( "Hope this helps you to understand the problem.<BR>\n" );
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document.write( " </SPAN>\n" );
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